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What is the probability that an ordinary year has 53 Sundays?

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Best answer
Ordinary year has 365 days

365 days = 52 weeks + 1 day

That 1 day may be Sun, Mon, Tue, Wed, Thu, Fri, Sat

Total no. of possible outcomes = 7

Let E ⟶ event of getting 53 Sundays

No. of favourable outcomes = 1 {Sun}

P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 1/7

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