By splitting the figure into four rectangles, we get Fig. 6.3

Area of the figure = Area AJIY + Area YWCB + Area DWUE + Area FUHG.

Area A J I Y = A J × J I = 3 × 3 = 9

Now, B Y = A B – Y A = 4 – 3 = 1

So, Area Y W C B = B Y × B C = 1 × 2 = 2

Next, D W = D C + C W = 2 + 1 = 3

Therefore, area D W U E = D W × D E = 3 × 3 = 9

Similarly, U H = I H – I U = 4 – 2 = 2

G H = F U and F U = E U + F E

= D W + F E = 3 + 1= 4

Area F U H G = U H × G H = 2 × 4 = 8

Therefore, the area of the figure = 9 + 2 + 9 + 8 = 28 sq units.