By splitting the figure into four rectangles, we get Fig. 6.3
Area of the figure = Area AJIY + Area YWCB + Area DWUE + Area FUHG.
Area A J I Y = A J × J I = 3 × 3 = 9
Now, B Y = A B – Y A = 4 – 3 = 1
So, Area Y W C B = B Y × B C = 1 × 2 = 2
Next, D W = D C + C W = 2 + 1 = 3
Therefore, area D W U E = D W × D E = 3 × 3 = 9
Similarly, U H = I H – I U = 4 – 2 = 2
G H = F U and F U = E U + F E
= D W + F E = 3 + 1= 4
Area F U H G = U H × G H = 2 × 4 = 8
Therefore, the area of the figure = 9 + 2 + 9 + 8 = 28 sq units.
