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A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) Minor segment

(ii) Major sector

 [Use π = 3.14]

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Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OADB =

=3/4 x 3.14 x 10 x 10


Area of minor sector OACB =


=1/4 x 3.14 x 10 x 10

= 78.5cm2

Area of trangle OAB = 

=50 cm2

Area of minor segment ACB = Area of minor sector OACB - Area of ΔOAB = 78.5 - 50 = 28.5 cm2

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