Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OADB =

=3/4 x 3.14 x 10 x 10

=235.5cm^{2}

Area of minor sector OACB =

=1/4 x 3.14 x 10 x 10

= 78.5cm^{2}

Area of trangle OAB =

=50 cm^{2}

Area of minor segment ACB = Area of minor sector OACB - Area of ΔOAB = 78.5 - 50 = 28.5 cm^{2}