Total number of possible outcomes = 12 {3 red balls, 5 black balls & 4 white balls}
(i) E ⟶ event of getting white ball
No. of favourable outcomes = 4 {4 white balls}
Probability, P(E) = 4/12 = 1/3
(ii) E ⟶ event of getting red ball
No. of favourable outcomes = 5 {3 red balls}
P (E) = 3/12 = 1/4
(iii) E ⟶ event of getting black ball
No. of favourable outcomes = 5 {5 black balls}
P (E) = 5/12
(iv) E ⟶ event of getting red
No. of favourable outcomes = 3 {3 black balls}
P(E) = 3/12 = 1/4
(Bar E) ⟶ event of not getting red.
P(Bar E) = 1 – P(E)
= 1 – 1/4
= 3/4