Step I.
Calculation of mass of CO2 produced
Mass of compound = 0.20 g
Percentage of carbon = 69 g
Percentage of carbon = \(\frac{12}{44}\) = \(\frac{Mass\,of\,carbon\,dioxide\,formed}{Mass\,of\,compound}\) x 100
69 = \(\frac{12}{44}\) = \(\frac{Mass\,of\,carbon\,dioxide\,formed}{(0.20\,g)}\) x 100
Mass of CO2 formed = \(\frac{69\times44\times(0.20g)}{12\times100}\) = 0.506 g
Step II.
Calculation of mass of H2O produced
Mass of compound = 0.20 g
Percentage of hydrogen = 4.8%
4.8 = \(\frac{2}{18}\) x \(\frac{Mass\,of\,water\,formed}{Mass\,of\,compound}\) x 100
Mass of H2O formed = \(\frac{4.8\times18\times(0.20g)}{2\times100}\) = 0.0864 g