Question

A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?

Answer 1

Total no. of possible outcomes = 18 {6 red, 8 black, 4 white}

Let E ⟶ event of drawing black ball.

No. of favourable outcomes = 8 {8 black balls}

Probability, P(E) = (No. of favorable outcomes)/(Total no. of possible outcomes) = 8/18 = 4/9

Bar E⟶ event of not drawing black ball

P(Bar E)=1 − P(E)

= 1 − 4/9 = 5/9