h = ?, R = 6400 km
g' = g\(\big(1-\frac{2h}{R}\big)\)= g - \(\frac{2gh}{R}\)
or g - g' = \(\frac{2gh}{R}\)
Percentage decrease in weight
= \(\frac{mg-mg'}{mg}\) x 100
= \(\frac{g-g'}{g}\) x 100
\(\frac{g-g'}{g}\) x 100 = \(\frac{2gh}{gR}\) x 100
= \(\frac{2h}{R}\times100\)
36 = \(\frac{2\times h}{6400}\times100\)
or h = 1.152 km