Let us consider the following diagram, the earth moves from the point A to B in one solar day.
Every day the earth advances in the orbit by approximately 1º . Then, it will have to rotate by 361º (which we define as 1 day) to have sun at zenith point again. Since 361º corresponds to 24 hours.
\(\therefore\) Extra 1º corresponds to approximately 4 minutes [3 min 59 seconds].
i.e. \(\frac{24}{361}\times1\) = 0.666 h = 3.99 min = 4 min
Thus, distant stars would rise 4 minutes early every successive day.