Total no. of possible outcomes = 15 {4 red, 5 black, 6 white balls}
(i) E ⟶ event of drawing white ball.
No. of favourable outcomes = 6 {6 white}
Probability, P(E) = (No. of favorable outcomes)/(Total no.of possible outcomes)
P(E) = 6/15 = 2/5
(ii) E ⟶ event of drawing red ball
No. of favourable outcomes = 4 {4 red balls}
P(E) = 4/15
(iii) E ⟶ event of drawing black ball
No. of favourable outcomes = 5 {5 black balls}
P(E) = 5/15 = 1/3
Bar E⟶ event of not drawing black ball
P(Bar E) = 1 − 1/3 = 2/3
(iv) E ⟶ event of drawing red or white ball
No. of favourable outcomes = 10 {4 red & 6 white}
P(E) = 10/15 = 2/3
