Radius (r) of circle = 15 cm
Area of sector OPRQ =
=1/6 x 3.14 x (15)2
=117.75 cm2
= In ΔOPQ,
∠OPQ = ∠OQP (As OP = OQ)
∠OPQ + ∠OQP + ∠POQ = 180°
2 ∠OPQ = 120°
∠OPQ = 60°
ΔOPQ is an equilateral triangle.
Area of ΔOPQ =
Area of segment PRQ = Area of sector OPRQ − Area of ΔOPQ
= 117.75 − 97.3125
= 20.4375 cm2
Area of major segment PSQ = Area of circle − Area of segment PRQ