Let us draw a perpendicular OV on chord ST. It will bisect the chord ST.
SV = VT
In ΔOVS,
Area of ΔOST = 1/2 x ST x VT
=1/2 x 12√3 x 6
= 36√3 = 36 x 1.73 = 62.28 cm2
Area of sector OSUT =
1/3 x 3.14 x 144 = 150.72 cm2
Area of segment SUT = Area of sector OSUT − Area of ΔOST
= 150.72 − 62.28
= 88.44 cm2