Total no. of days to visit the shop = 6 {Mon to Sat}

Total no. possible outcomes = 6×6 = 36

i.e. two customers can visit the shop in 36 ways

**(i) E⟶ event of visiting shop on the same day.**

No. of favourable outcomes = 6 which are (M, M) (T, T) (Th, Th) (F, F) (S, S)

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)

P(E) = 6/36 = 1/6

**(ii) E⟶ event of visiting shop on the same day.**

E⟶ event of visiting shop on the different days.

In above bit, we calculated P(E) as 1/6

We know that, P(E) + P(Bar E) = 1

P(Bar E) = 1 – P(E)

= 1−1/6 = 5/6

**(iii) E⟶ event of visiting shop on c**

No. of favourable outcomes = 5 which are (M, T) (T, W) (W, Th) (Th, F) (F, S)

P(E) = 5/36