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1.6k views
in Geometry by (9.2k points)

Draw any line segment PQ. Take any point R not on it. Through R, draw a perpendicular to PQ.

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1 Answer

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by (15.8k points)

Construction:

(i) Drawn a line segment PQ using scale and taken a point R outside of PQ.

(ii) Placed a set-square on PQ such that one arm of its right angle aligns along PQ.

(iii) Placed a scale along the other edge of the right angle of the set-square

(iv) Slide the set-square along the line till the point R touches the other arm of its right angle.

(v) Joined RS along the edge through R meeting PQ at S.

Hence RS ⊥ PQ.

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