Given no’s are 1, 2, 2, 3, 3, 3, 4, 4, 4, 4

Total no. of possible outcomes = 10

Average of the no’s = (sum of no's)/( total no's) = (1+2+2+3+3+3+4+4+4+4)/10 = 30/10 = 3

E ⟶ event of getting 3

No. of favourable outcomes = 3 {3, 3, 3}

P(E) = (No. of favorable outcomes)/(Total no. of possible outcomes)

P(E) = 3/10