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It is given that m a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

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Let E ⟶ event of 2 students having same birthday P(E) is given as 0.992

Let (Bar E) ⟶ event of 2 students not having same birthday.

We know that, P(E) + P(Bar E)=1

P(Bar E)=1−P(E)

= 1 – 0.992

= 0.008

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