Question

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is

(i) red?

(ii) not red?

Answer 1

Total no. of possible outcomes = 8 {3 red, 5 black}

(i) E ⟶ event of getting red ball.

No. of favourable outcomes = 3 {3 red}

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)

P(E) = 3/8

(ii) Bar E ⟶ event of getting no red ball.

()+P(Bar E)=1

P(̅)=1−P(Bar E)

= 1 − 3/8 = 5/8