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+1 vote
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in Permutations and combinations by (235 points)
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7 relatives of a man comprises 4 ladies and 3 gentlemen; his wife has also 7 relative; 3 of them are ladies and 4 gentlemen.

1 Answer

+2 votes
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Best answer

The possible cases are:

Case I : A man invites (3 ladies) and woman invites (3 gentlemen)

4C3 4C3 = 16

Case II : A man invites (2 ladies,1 gentleman) and woman invites (2 gentleman, 1 lady)

(4C23C1)(3C14C2) = 324

Case III :   A man invites (1 lady, 2 gentlemen) and woman invites (2 ladies, 1 gentleman)

⇒ (4C13C2)(3C24C1) = 144

Case IV :   A man invites (3 gentlemen) and woman invites (3 ladies)

3C3 3C3 = 1

Total number of ways

= 16 + 324 + 144 + 1 = 485

by (10 points)
Thank you.

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