No. of good pens = 132
No. of defective pens = 12
Total no. of possible outcomes = 12 + 12 {total no of pens}
E ⟶ event of getting a good pen.
No. of favourable outcomes = 132 {132 good pens}
P (E) = (No.of favorable outcomes)/(Total no.of possible outcomes)
∴ P(E) = 132/144 = 66/72 = 33/36 = 11/12