Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
830 views
in Solutions by (28.2k points)
closed by

(a) Number of moles of the solute per kilogram of the solvent is  

(a) Mole fraction 

(b) Molality 

(c) Molarity 

(d) Molar mass

(b) The extent to which a solute is dissociated or associated can be expressed by Van’t Ho factor.’ Substantiate the statement. 

(c) The vapour pressure of pure benzene at a certain temperature is0.850 bar. Anon volatile, non-electrolyte solid weighing 0.5 g when added to 39 g of benzene (molar mass 78 g mol-1 ), the vapour pressure becomes 0.845 bar. What is the molar mass of the solid substance?

1 Answer

+1 vote
by (28.9k points)
selected by
 
Best answer

(a) (b) Molality

(b) (b) The van’t Holf factor,

When i = 1 ⇒ there is no association or dissociation of solute particles.
When i < 1 ⇒ there is association of solute particles. When i > 1 ⇒ there is dissociation of solute particles.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...