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Find the area of the shaded region in the given figure, if PQ = 24 cm, PR = 7 cm and O is the centre of the circle. [Use π =22/7]

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It can be observed that RQ is the diameter of the circle. Therefore, ∠RPQ will be 90º.

By applying Pythagoras theorem in ΔPQR,

RP2 + PQ2 = RQ2

(7)2 + (24)2 = RQ2

Radius of circle, 

Since RQ is the diameter of the circle, it divides the circle in two equal parts.

Area of ΔPQR = 1/2 x PQ x PR

                        =1/2 x 24 x 7

                        = 84 cm

Area of shaded region = Area of semi-circle RPQOR − Area of ΔPQR

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