Question

A train is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of – 0.5 m/s ² . Find how far the train will go before it is brought to rest.

Answer 1

Here, we have, 

Initial velocity, u = 90 km/h = 90×1000 / 3600 ms ⁻¹ = 25 ms ⁻¹ 

Final velocity, v = 0 m/s 

Acceleration, a = – 0.5 m/s² 

Distance travelled = ? 

Using, v 2 = u 2 + 2as

Therefore, train will go 625 m before it brought to rest.