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A train is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of – 0.5 m/s 2 . Find how far the train will go before it is brought to rest.

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Here, we have, 

Initial velocity, u = 90 km/h = 90×1000 / 3600 ms −1 = 25 ms −1 

Final velocity, v = 0 m/s 

Acceleration, a = – 0.5 m/s

Distance travelled = ? 

Using, v 2 = u 2 + 2as

Therefore, train will go 625 m before it brought to rest.

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