Sarthaks Test
0 votes
in Physics by (38.1k points)

The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is  ve=c/100. Then

(a) Ee/Ep=10-4

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

(d) Pe/meC=10-4

1 Answer

0 votes
by (63.6k points)
selected by
Best answer

(b), (c)

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.