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in Physics by (38.8k points)

The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is  ve=c/100. Then

(a) Ee/Ep=10-4

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

(d) Pe/meC=10-4

1 Answer

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Best answer

(b), (c)

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

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