# A body is projected with speed u at an angle θ to the horizontal to have maximum range. What is the velocity at the highest point?

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A body is projected with speed u at an angle θ to the horizontal to have maximum range. What is the velocity at the highest point?

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for maximum horizontal range, θ = 45º,

Velocity at highest point = Horizontal component of velocity = ucos 45º$=\frac{u}{\sqrt2}$