Sarthaks Test
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From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in the given figure. Find the area of the remaining portion of the square.[Use π =22/7]

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Each quadrant is a sector of 90° in a circle of 1 cm radius.

Area of each quadrant 

Area of square = (Side)2 = (4)2 = 16 cm2

Area of circle = πr2 = π (1)2 =22/7 cm2

Area of the shaded region = Area of square − Area of circle − 4 × Area of quadrant

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