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2tan−1\(\frac{1}{2}\) + tan−1\(\frac{1}{7}\)=tan−1\(\frac{31}{7}\)

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LHS = 2tan -1\(\frac{1}{2}\) + tan-1\(\frac{1}{7}\)

= tan-1 \(\frac{28+3}{21-4}\) = tan-1 \(\frac{31}{7}\)

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