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Prove that \(\vec A.\vec B=\vec B. \vec A\).

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Let θ is the angle between \(\vec A\) and \(\vec B\).

∴ \(\vec A.\vec B=AB\,cos\,\theta\)    ...(i)

and \(\vec B.\vec A=BA\,cos\,\theta\)  ...(ii)

from eqn. (i) and (ii),

\(\vec A.\vec B=\vec B.\vec A\)

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