(i) sin-1 \((\frac{1}{2})\) = \(\frac{π}{6}\)
(ii) Let sin-1 (\(\frac{3}{5}\)) = x and sin-1 (\(\frac{8}{17}\)) = y
sin x = \(\frac{3}{5}\) ⇒ cos x = \(\sqrt{1-sin^2x}\)
= \(\sqrt{1- (\frac {3}{5})^2}\) = \(\frac{4}{5}\) ; sin y = \(\frac{8}{17}\)
cos (x - y) = cos x cos y + sin x sin y
=