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in Inverse Trigonometric Functions by (28.2k points)
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(i) Give an expression for tan(x + y) 

(ii) Prove that xy < 1,

tan-1x + tan-1y = tan-1 (\(\frac{x+y}{1-xy}\))

(iii) Using the above result prove that

tan-1 \(\frac{1}{2}\) + tan-1\(\frac{1}{3}\) = \(\frac{π}{4}\)

1 Answer

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by (28.9k points)
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Best answer

(ii) Let tan-1x = A and tan-1y = B

⇒ tan A = x, tan B = y

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