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Find HCF of the following pair of numbers by Euclid’s game.

(i) 25 and 35

(ii) 36 and 12

(iii) 15 and 29

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(i) HCF of (25, 35 – 25)

25 = 5 × 5

10 = 2 × 5

HCF of (25, 10) = 5

(ii) HCF of (36, 36 – 12)

36 = 2 × 2 × 3 × 3

24 = 2 × 2 × 2 × 3

HCF of (36, 24) = 2 × 2 × 3 = 12

(iii) HCF of (15, 29 -15)

15 = 3 × 5 × 1

14 = 2 × 7 × 1

HCF of (15, 14) = 1

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