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in Inverse Trigonometric Functions by (28.2k points)
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(i) Show that tan−1 \(\frac{1}{5}\) + tan−1\(\frac{1}{7}\) + tan−1\(\frac{1}{3}\) + tan−1\(\frac{1}{8}\) = \(\frac{π}{4}\)

(ii) Given that Cot 3θ = \(\frac{3cot^2 θ -1}{cot^3 θ - 3cot θ'}\)

cot-1 \(\frac{3x^2 θ -1}{x^3 θ - 3x θ'}\) , |x|<√3 is 3cot1 x

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(ii) Put x = cot θ ⇒ θ = cot-1x

= Cot -1 [cot 3θ] = 3θ = 3cot-1x

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