Question

Find the remainder left out when \(8^{2n}\) – \((62)^{2n+1}\) is divided by 9.

Answer 1

To get the remainder, when \(8^{2n}\) - \((62)^{2n+1}\)To get the remainder, when  is divided by 9, put n = 0

 We get, 

= \((8)^{2\times0} - (62)^{2\times0+1}\)

=\((8)^0 -(62)^1\)

= 62, 

when it is divided by 9 we get remainder as 2.