Question

A horizontal stream of water leaves an opening in the side of a tank. If the opening is made at a height 'h' above the ground and the stream hits the ground at a distance ‘D’. Then what is the speed of water as it leaves the tank in terms of g, h and D?

Answer 1

The stream of water leaving the tank behaves like a horizontal projectile and follows parabolic path.

 \(h=\frac{1}{2}gt^2\)  (∵ t = \(\sqrt{\frac{2h}{g}}\))

\(v=\frac{D}{t}=\sqrt[D]{\frac{g}{2h}}\)