The general term in the expansion of \((x^\frac{1}{5}+y^\frac{1}{10})^{55}\) is given by
Tr + 1 = 55Cr \((x^\frac{1}{5})^{55-r}\) \((y^\frac{1}{10})^{r}\)
Tr + 1 = 55Cr x11-r/5 \(y^\frac{r}{10}\)
Clearly, Tr + 1 will be free from radical signs, if \(\frac{r}{5}\) and \(\frac{r}{10}\)are integers for 0 ≤ r ≤ 55.
∴ r = 0, 10, 20, 30, 40, 50.
Hence, there are 6 terms in the expansion of \((x^\frac{1}{5}+y^\frac{1}{10})^{55}\) which are independent of radical sign.