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in Binomial Theorem by (3.3k points)
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Find the constant term in expansion \((x-\frac{1}{x})^{10}\) 

1 Answer

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Best answer

 Tr + 1 = 10Cr (x)10 – r \((\frac{-1}{x})^r\)

= 10Cr (x)10 – 2r (– 1)r 

= (– 1)r 10 Cr x10-2r

For the constant term, put 10 – 2r = 0 

We get, r = 5 

Hence, T5 + 1 = T6 i.eth term of the expansion is constant. 

T6 = T5 + 1 = 10C5 (– 1)5 x10 – 10

= -252

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