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in Binomial Theorem by (3.3k points)
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Find the 4th term from the end in the expansion of \((\frac{x^3}{2}-\frac{2}{x^3})^{9}\)

1 Answer

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Best answer

Since rth term from the end in the expansion of (a + b)n is (n – r + 2) th term from the beginning. Therefore 4th term from the end is 9 – 4 + 2, i. e., 7 th term from the beginning, which was given by

OR

4th term from the end of \((\frac{x^2}{2}-\frac{2}{x^3})^9\)

= 4th term from the beginning \((\frac{-2}{x^3}+\frac{x^2}{2})^9\)

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