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in Continuity and Differentiability by (28.9k points)
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(i) Check the continuity of the function given by f(x)

f(x) = \(\begin{cases}x sin {\frac{1}{x}} & x ≠ 0\\\ 1 & x = 0 \end{cases} \)

(ii) Verify Mean Value Theorem for the function f(x) = x + \(\frac{1}{x}\) in the interval [1,3].

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given ; f(o) = 1. So f (x) is discontinuous at x = 0

⇒ C2 = 3

⇒ C = \(\sqrt {3}\) ∈ (1,3)

Hence Mean Value Theorem ¡s verified.

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