Let (r + 1)th term be independent of x which is given by
Since the term is independent of x, we have
\(\frac{10-r}{2}\) - 2r = 0 ⇒ r = 2
Hence 3rd term is independent of and its value is given by
T3 = 10C2 \(\frac{3^{-3}}{4} = \frac{10\times9}{2\times1}\times\frac{1}{9\times12} = \frac{5}{12}\)