General term of \((2x^2-\frac{3}{x})^{11}\)
Tr + 1 = 11Cr (2x2 )11 – r \((\frac{-3}{x})^{r}\)
= 11Cr (-1)r 211-r 3r x22-3r
For term contain x6
22 – 3r = 6
R = \(\frac{16}{3}\)
∴ r is not natural number
∴ Expansion of \((2x^2-\frac{3}{x})^{11}\) is not contain x6 term