Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.5k views
in Three Dimensional Geometry by (4.0k points)
closed by

(i) Find the Cartesian equation of the plane passing through the point (1, 2, -3) perpendicular to the vector 2i – j + 2k. 

(ii) Find the angle between the above

\(\frac{x-1}{2}=\frac{y-3}{3}=\frac{z}{6}\)

1 Answer

+1 vote
by (3.3k points)
selected by
 
Best answer

(i) The equation of the Plane is 

2(x – 1) – 1(y, -2) + 2(z+3) = 0 

⇒ 2x – 2 – y + 2 + 2z + 6 = 0 

⇒ 2x – y + 2z + 6 – 0

(ii) Angle between the line and the Plane is

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...