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in Three Dimensional Geometry by (4.0k points)
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(i) The equation of the line which passes through the point(1,2,3) and parallels to the vector 3i + 2j – 2k is

(a) \(\bar{r}\) = 3i + 2j – 2k + λ(i + 2j + 3k)

(b) \(\bar{r}\) = 2i – 5k + λ(3i + 2j – 2k)

(c) \(\bar{r}\) = i + 2j + 3k + λ(-2i + 4j – 2k) 

(d) \(\bar{r}\) = i + 2j + 3k + λ(3i + 2j – 2k)

 (ii) Find the angle between the pair lines 

\(\bar{r}\) = 2i – 5j + k + λ(3i + 2j + 6k) and \(\bar{r}\)= li – 6k + µ(i + 2j + 2k)

1 Answer

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Best answer

(i) (d) \(\bar{r}\)= i + 2j + 3k + λ(3i + 2j – 2k)

(ii) \(\bar{a}\)= 3i + 2j + 6k; \(\bar{b}\) = = i + 2j + 2k

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