Lets the first number be x and another number be y.
According to the question:
\(\frac{1}{4} x = 5y\)
x = 20y
and \(\frac{x}{y} = \frac{20}{1}\)
x : y = 20 : 1
then x + y = 21
x = \(\frac{20}{21} \times 210\)
x = 20 x 10
x = 200
and y = \(\frac{1}{21} \times 210\)
y = 1 x 10
y = 10
Hence, first number is 200 and another number is 10.