(a) Let E1 be the event selecting box I and E2 be the event selecting box II.
\(P\left(A / E_{1}\right)=\frac{1}{2} \times \frac{5}{9}=\frac{5}{18}\)
\(P\left(A / E_{2}\right)=\frac{1}{2} \times \frac{3}{6}=\frac{3}{12}\)
P (taking a red ball)
\(\frac{5}{18}+\frac{3}{12}=\frac{19}{36}\)
b) Let B be the event selecting a black ball