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in Application of Integrals by (28.9k points)
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Find the area enclosed between the curve x2 = 4y and the line x = 4y – 2

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Best answer

The point of intersection of x2 = 4y and

x = 4y - 2 is ⇒ x = x2 - 2

⇒ x2 - x - 2 =0 ⇒ (x - 2) (x + 1) = 0

⇒ x = -1,2, 

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