(1) S = { HHH , HHT ,HTH, THH, HTT , THT , HTH , TTT)
Let X denotes the random variable of getting a Head. Then X can take values 0,1 ,2,3.
P(X = 0) = P(no Heads)
= P({TTT})
P(X = 3 ) = P(3 Heads)
= \(P(H)\times P(H)\times P(H)\\=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\\=\frac{1}{8}\)
(ii) Let X denotes the random variable of number of defective items. Clearly X has a Binomial Distribution with n = 10