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+1 vote
5.9k views
in Linear Programming by (3.3k points)
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Consider the LPP Minimise; Z = 200 k + 500y, x + 2y > 10, 3x + 4y < 24, x > 0, y > 0 

(i) Draw the feasible region. 

(ii) Find the co-ordinates of the comer points of the feasible region. 

(iii) Solve the LPP

1 Answer

+2 votes
by (4.0k points)
selected by
 
Best answer

(i) 

(ii) In the figure the shaded region ABC is the feasible region. Here the region is bounded. The corner points are 4(4, 3), 5(0, 6), C(0, 5)

(iii) Given; Z = 200x + 500y

Corner points

Value of Z

A

Z = 200(4)+500(3) = 2300

B

Z = 200(0)+500(6) = 3000

C

Z = 200(0)+500(5) = 2500

Since minimum value of Z occurs at A, the soluion is Z = 200(4) + 500(3) = 2300.

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