(i)
(ii) In the gure the shaded region ABC is the feasible region. Here the region is bounded. The corner points are A(4, 3), B(0, 6), C(0, 5)
(iii) Given; Z = 50x + 40y
Corner points |
Value of Z |
A |
Z = 50(4)+ 40(3) = 320 |
B |
Z= 50(0)+ 40(6) = 240 |
C |
Z= 50(0)+ 40(5) = 200 |
Since minimum value of Z occurs at A, the solution is
Z = 50(4) + 4(3) = 320