(i) Let x be the number of Tables and y be the number of Chairs. Then; Maximise; z = 75x + 25y
(ii) Furniture constraints x + y < 90
Investment constraint 400x + 100y < 12000
Therefore;Maximise; Z = 75x + 25y, x + y < 90, 4x + y < 120, x<0, y<0
(iii) In the figure the shaded region OABC is the feasible region. Here the region is bounded. The corner points are O(0, 0), A(30, 0) B(10, 80), C(0, 90)
Given; Z = 75x + 25y
Corner points |
Value of Z |
O |
Z =75(0) +25(0) = 0 |
A |
Z= 75(30)+ 25(0) = 2250 |
B |
Z= 75(10)+ 25(80) = 2750 |
C |
Z= 75(0)+ 25(90) = 2250 |
Since minimum value of Z occurs at B, the soluion is Z = 2750.