Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
608 views
in Physics by (34.4k points)
closed by

A pendulum is mounted on a cart rolling without friction down on an inclined surface of inclination θ with the horizontal. The period of the pendulum on an immobile cart is T. what will be the period of the pendulum on the cart when the cart rolls down the surface?

1 Answer

+1 vote
by (34.9k points)
selected by
 
Best answer

When the cart is at rest, the effective acceleration due to gravity is g and when the cart is rolling down the inclined surface, the effective acceleration due to gravity involved perpendicular to plane is g cos θ. Time period of pendulum when art is immobile,

T = \(2\pi\sqrt{\frac{l}{g}}\)

Time period of cart when it moving down the plane,

T’= \(2\pi\sqrt{\frac{l}{g\,cos\,\theta}}\)

Or  T' = \(\frac{T}{\sqrt {cos \theta}}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...