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in Linear Programming by (3.3k points)
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In a factory, there are two machines A and B producing toys. They respectively produce 60 and 80 units in one hour. A can run a maximum of 10 hours and B a maximum of 7 hours a day. The cost of their running per hour respectively amounts to 2,000 and 2,500 rupees. The total duration of working these machines cannot exceed 12 hours a day. If the total cost cannot exceed Rs. 25,000 per day and the total daily production is at least 800 units, then formulate the problem mathematically

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Let x be the running time for machine A and y be the running time for machine B. Since machines cannot work more than 12 hours x + y < 12 

Since maximum production of two machines is 800 units. 60x + 80y < 800 

Maximum cost of production is 25000, 

2000x + 2500y < 25000 0 < x < 10, 0 < y < 7

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